Optimal. Leaf size=255 \[ \frac{b \left (1920 a^2+12312 a b+10579 b^2\right ) \sinh (c+d x) \cosh ^5(c+d x)}{3840 d}-\frac{b \left (4992 a^2+10728 a b+5549 b^2\right ) \sinh (c+d x) \cosh ^3(c+d x)}{3072 d}+\frac{\left (4224 a^2 b+1024 a^3+4632 a b^2+1619 b^3\right ) \sinh (c+d x) \cosh (c+d x)}{2048 d}-\frac{x \left (1920 a^2 b+1024 a^3+1512 a b^2+429 b^3\right )}{2048}+\frac{b^2 (504 a+2593 b) \sinh (c+d x) \cosh ^9(c+d x)}{1680 d}-\frac{b^2 (6888 a+11821 b) \sinh (c+d x) \cosh ^7(c+d x)}{4480 d}+\frac{b^3 \sinh (c+d x) \cosh ^{13}(c+d x)}{14 d}-\frac{85 b^3 \sinh (c+d x) \cosh ^{11}(c+d x)}{168 d} \]
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Rubi [A] time = 0.557087, antiderivative size = 255, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 6, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.261, Rules used = {3217, 1257, 1814, 1157, 385, 206} \[ \frac{b \left (1920 a^2+12312 a b+10579 b^2\right ) \sinh (c+d x) \cosh ^5(c+d x)}{3840 d}-\frac{b \left (4992 a^2+10728 a b+5549 b^2\right ) \sinh (c+d x) \cosh ^3(c+d x)}{3072 d}+\frac{\left (4224 a^2 b+1024 a^3+4632 a b^2+1619 b^3\right ) \sinh (c+d x) \cosh (c+d x)}{2048 d}-\frac{x \left (1920 a^2 b+1024 a^3+1512 a b^2+429 b^3\right )}{2048}+\frac{b^2 (504 a+2593 b) \sinh (c+d x) \cosh ^9(c+d x)}{1680 d}-\frac{b^2 (6888 a+11821 b) \sinh (c+d x) \cosh ^7(c+d x)}{4480 d}+\frac{b^3 \sinh (c+d x) \cosh ^{13}(c+d x)}{14 d}-\frac{85 b^3 \sinh (c+d x) \cosh ^{11}(c+d x)}{168 d} \]
Antiderivative was successfully verified.
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Rule 3217
Rule 1257
Rule 1814
Rule 1157
Rule 385
Rule 206
Rubi steps
\begin{align*} \int \sinh ^2(c+d x) \left (a+b \sinh ^4(c+d x)\right )^3 \, dx &=\frac{\operatorname{Subst}\left (\int \frac{x^2 \left (a-2 a x^2+(a+b) x^4\right )^3}{\left (1-x^2\right )^8} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac{b^3 \cosh ^{13}(c+d x) \sinh (c+d x)}{14 d}+\frac{\operatorname{Subst}\left (\int \frac{-b^3+14 \left (a^3-b^3\right ) x^2-14 \left (5 a^3+b^3\right ) x^4+14 \left (10 a^3+3 a^2 b-b^3\right ) x^6-14 \left (10 a^3+9 a^2 b+b^3\right ) x^8+14 (5 a-b) (a+b)^2 x^{10}-14 (a+b)^3 x^{12}}{\left (1-x^2\right )^7} \, dx,x,\tanh (c+d x)\right )}{14 d}\\ &=-\frac{85 b^3 \cosh ^{11}(c+d x) \sinh (c+d x)}{168 d}+\frac{b^3 \cosh ^{13}(c+d x) \sinh (c+d x)}{14 d}-\frac{\operatorname{Subst}\left (\int \frac{-73 b^3-168 \left (a^3+5 b^3\right ) x^2+672 \left (a^3-b^3\right ) x^4-504 \left (2 a^3+a^2 b+b^3\right ) x^6+336 (2 a-b) (a+b)^2 x^8-168 (a+b)^3 x^{10}}{\left (1-x^2\right )^6} \, dx,x,\tanh (c+d x)\right )}{168 d}\\ &=\frac{b^2 (504 a+2593 b) \cosh ^9(c+d x) \sinh (c+d x)}{1680 d}-\frac{85 b^3 \cosh ^{11}(c+d x) \sinh (c+d x)}{168 d}+\frac{b^3 \cosh ^{13}(c+d x) \sinh (c+d x)}{14 d}+\frac{\operatorname{Subst}\left (\int \frac{-9 b^2 (56 a+207 b)+1680 \left (a^3-3 a b^2-10 b^3\right ) x^2-5040 \left (a^3+a b^2+2 b^3\right ) x^4+5040 (a-b) (a+b)^2 x^6-1680 (a+b)^3 x^8}{\left (1-x^2\right )^5} \, dx,x,\tanh (c+d x)\right )}{1680 d}\\ &=-\frac{b^2 (6888 a+11821 b) \cosh ^7(c+d x) \sinh (c+d x)}{4480 d}+\frac{b^2 (504 a+2593 b) \cosh ^9(c+d x) \sinh (c+d x)}{1680 d}-\frac{85 b^3 \cosh ^{11}(c+d x) \sinh (c+d x)}{168 d}+\frac{b^3 \cosh ^{13}(c+d x) \sinh (c+d x)}{14 d}-\frac{\operatorname{Subst}\left (\int \frac{-231 b^2 (72 a+89 b)-13440 \left (a^3+9 a b^2+10 b^3\right ) x^2+26880 (a-2 b) (a+b)^2 x^4-13440 (a+b)^3 x^6}{\left (1-x^2\right )^4} \, dx,x,\tanh (c+d x)\right )}{13440 d}\\ &=\frac{b \left (1920 a^2+12312 a b+10579 b^2\right ) \cosh ^5(c+d x) \sinh (c+d x)}{3840 d}-\frac{b^2 (6888 a+11821 b) \cosh ^7(c+d x) \sinh (c+d x)}{4480 d}+\frac{b^2 (504 a+2593 b) \cosh ^9(c+d x) \sinh (c+d x)}{1680 d}-\frac{85 b^3 \cosh ^{11}(c+d x) \sinh (c+d x)}{168 d}+\frac{b^3 \cosh ^{13}(c+d x) \sinh (c+d x)}{14 d}+\frac{\operatorname{Subst}\left (\int \frac{-105 b \left (384 a^2+1512 a b+941 b^2\right )+80640 (a-5 b) (a+b)^2 x^2-80640 (a+b)^3 x^4}{\left (1-x^2\right )^3} \, dx,x,\tanh (c+d x)\right )}{80640 d}\\ &=-\frac{b \left (4992 a^2+10728 a b+5549 b^2\right ) \cosh ^3(c+d x) \sinh (c+d x)}{3072 d}+\frac{b \left (1920 a^2+12312 a b+10579 b^2\right ) \cosh ^5(c+d x) \sinh (c+d x)}{3840 d}-\frac{b^2 (6888 a+11821 b) \cosh ^7(c+d x) \sinh (c+d x)}{4480 d}+\frac{b^2 (504 a+2593 b) \cosh ^9(c+d x) \sinh (c+d x)}{1680 d}-\frac{85 b^3 \cosh ^{11}(c+d x) \sinh (c+d x)}{168 d}+\frac{b^3 \cosh ^{13}(c+d x) \sinh (c+d x)}{14 d}-\frac{\operatorname{Subst}\left (\int \frac{-315 b \left (1152 a^2+1560 a b+595 b^2\right )-322560 (a+b)^3 x^2}{\left (1-x^2\right )^2} \, dx,x,\tanh (c+d x)\right )}{322560 d}\\ &=\frac{\left (1024 a^3+4224 a^2 b+4632 a b^2+1619 b^3\right ) \cosh (c+d x) \sinh (c+d x)}{2048 d}-\frac{b \left (4992 a^2+10728 a b+5549 b^2\right ) \cosh ^3(c+d x) \sinh (c+d x)}{3072 d}+\frac{b \left (1920 a^2+12312 a b+10579 b^2\right ) \cosh ^5(c+d x) \sinh (c+d x)}{3840 d}-\frac{b^2 (6888 a+11821 b) \cosh ^7(c+d x) \sinh (c+d x)}{4480 d}+\frac{b^2 (504 a+2593 b) \cosh ^9(c+d x) \sinh (c+d x)}{1680 d}-\frac{85 b^3 \cosh ^{11}(c+d x) \sinh (c+d x)}{168 d}+\frac{b^3 \cosh ^{13}(c+d x) \sinh (c+d x)}{14 d}-\frac{\left (1024 a^3+1920 a^2 b+1512 a b^2+429 b^3\right ) \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\tanh (c+d x)\right )}{2048 d}\\ &=-\frac{\left (1024 a^3+1920 a^2 b+1512 a b^2+429 b^3\right ) x}{2048}+\frac{\left (1024 a^3+4224 a^2 b+4632 a b^2+1619 b^3\right ) \cosh (c+d x) \sinh (c+d x)}{2048 d}-\frac{b \left (4992 a^2+10728 a b+5549 b^2\right ) \cosh ^3(c+d x) \sinh (c+d x)}{3072 d}+\frac{b \left (1920 a^2+12312 a b+10579 b^2\right ) \cosh ^5(c+d x) \sinh (c+d x)}{3840 d}-\frac{b^2 (6888 a+11821 b) \cosh ^7(c+d x) \sinh (c+d x)}{4480 d}+\frac{b^2 (504 a+2593 b) \cosh ^9(c+d x) \sinh (c+d x)}{1680 d}-\frac{85 b^3 \cosh ^{11}(c+d x) \sinh (c+d x)}{168 d}+\frac{b^3 \cosh ^{13}(c+d x) \sinh (c+d x)}{14 d}\\ \end{align*}
Mathematica [A] time = 0.680134, size = 189, normalized size = 0.74 \[ \frac{-840 \left (1920 a^2 b+1024 a^3+1512 a b^2+429 b^3\right ) (c+d x)-105 b \left (2304 a^2+2880 a b+1001 b^2\right ) \sinh (4 (c+d x))+35 b \left (768 a^2+2160 a b+1001 b^2\right ) \sinh (6 (c+d x))+105 \left (11520 a^2 b+4096 a^3+10080 a b^2+3003 b^3\right ) \sinh (2 (c+d x))-105 b^2 (120 a+91 b) \sinh (8 (c+d x))+21 b^2 (48 a+91 b) \sinh (10 (c+d x))-245 b^3 \sinh (12 (c+d x))+15 b^3 \sinh (14 (c+d x))}{1720320 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.054, size = 240, normalized size = 0.9 \begin{align*}{\frac{1}{d} \left ({b}^{3} \left ( \left ({\frac{ \left ( \sinh \left ( dx+c \right ) \right ) ^{13}}{14}}-{\frac{13\, \left ( \sinh \left ( dx+c \right ) \right ) ^{11}}{168}}+{\frac{143\, \left ( \sinh \left ( dx+c \right ) \right ) ^{9}}{1680}}-{\frac{429\, \left ( \sinh \left ( dx+c \right ) \right ) ^{7}}{4480}}+{\frac{143\, \left ( \sinh \left ( dx+c \right ) \right ) ^{5}}{1280}}-{\frac{143\, \left ( \sinh \left ( dx+c \right ) \right ) ^{3}}{1024}}+{\frac{429\,\sinh \left ( dx+c \right ) }{2048}} \right ) \cosh \left ( dx+c \right ) -{\frac{429\,dx}{2048}}-{\frac{429\,c}{2048}} \right ) +3\,a{b}^{2} \left ( \left ( 1/10\, \left ( \sinh \left ( dx+c \right ) \right ) ^{9}-{\frac{9\, \left ( \sinh \left ( dx+c \right ) \right ) ^{7}}{80}}+{\frac{21\, \left ( \sinh \left ( dx+c \right ) \right ) ^{5}}{160}}-{\frac{21\, \left ( \sinh \left ( dx+c \right ) \right ) ^{3}}{128}}+{\frac{63\,\sinh \left ( dx+c \right ) }{256}} \right ) \cosh \left ( dx+c \right ) -{\frac{63\,dx}{256}}-{\frac{63\,c}{256}} \right ) +3\,{a}^{2}b \left ( \left ( 1/6\, \left ( \sinh \left ( dx+c \right ) \right ) ^{5}-{\frac{5\, \left ( \sinh \left ( dx+c \right ) \right ) ^{3}}{24}}+{\frac{5\,\sinh \left ( dx+c \right ) }{16}} \right ) \cosh \left ( dx+c \right ) -{\frac{5\,dx}{16}}-{\frac{5\,c}{16}} \right ) +{a}^{3} \left ({\frac{\cosh \left ( dx+c \right ) \sinh \left ( dx+c \right ) }{2}}-{\frac{dx}{2}}-{\frac{c}{2}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.21768, size = 597, normalized size = 2.34 \begin{align*} -\frac{1}{8} \, a^{3}{\left (4 \, x - \frac{e^{\left (2 \, d x + 2 \, c\right )}}{d} + \frac{e^{\left (-2 \, d x - 2 \, c\right )}}{d}\right )} - \frac{1}{3440640} \, b^{3}{\left (\frac{{\left (245 \, e^{\left (-2 \, d x - 2 \, c\right )} - 1911 \, e^{\left (-4 \, d x - 4 \, c\right )} + 9555 \, e^{\left (-6 \, d x - 6 \, c\right )} - 35035 \, e^{\left (-8 \, d x - 8 \, c\right )} + 105105 \, e^{\left (-10 \, d x - 10 \, c\right )} - 315315 \, e^{\left (-12 \, d x - 12 \, c\right )} - 15\right )} e^{\left (14 \, d x + 14 \, c\right )}}{d} + \frac{720720 \,{\left (d x + c\right )}}{d} + \frac{315315 \, e^{\left (-2 \, d x - 2 \, c\right )} - 105105 \, e^{\left (-4 \, d x - 4 \, c\right )} + 35035 \, e^{\left (-6 \, d x - 6 \, c\right )} - 9555 \, e^{\left (-8 \, d x - 8 \, c\right )} + 1911 \, e^{\left (-10 \, d x - 10 \, c\right )} - 245 \, e^{\left (-12 \, d x - 12 \, c\right )} + 15 \, e^{\left (-14 \, d x - 14 \, c\right )}}{d}\right )} - \frac{3}{20480} \, a b^{2}{\left (\frac{{\left (25 \, e^{\left (-2 \, d x - 2 \, c\right )} - 150 \, e^{\left (-4 \, d x - 4 \, c\right )} + 600 \, e^{\left (-6 \, d x - 6 \, c\right )} - 2100 \, e^{\left (-8 \, d x - 8 \, c\right )} - 2\right )} e^{\left (10 \, d x + 10 \, c\right )}}{d} + \frac{5040 \,{\left (d x + c\right )}}{d} + \frac{2100 \, e^{\left (-2 \, d x - 2 \, c\right )} - 600 \, e^{\left (-4 \, d x - 4 \, c\right )} + 150 \, e^{\left (-6 \, d x - 6 \, c\right )} - 25 \, e^{\left (-8 \, d x - 8 \, c\right )} + 2 \, e^{\left (-10 \, d x - 10 \, c\right )}}{d}\right )} - \frac{1}{128} \, a^{2} b{\left (\frac{{\left (9 \, e^{\left (-2 \, d x - 2 \, c\right )} - 45 \, e^{\left (-4 \, d x - 4 \, c\right )} - 1\right )} e^{\left (6 \, d x + 6 \, c\right )}}{d} + \frac{120 \,{\left (d x + c\right )}}{d} + \frac{45 \, e^{\left (-2 \, d x - 2 \, c\right )} - 9 \, e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )}}{d}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.40475, size = 1688, normalized size = 6.62 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.70269, size = 756, normalized size = 2.96 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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